a path of a bball thrown at the free throw line is modeled by -0.06x^2+1.5x+6 where y is the height find the mx height
y = -0.06x^2 + 1.5x + 6
Maximum height = -b/2a where a = -0.06 and b = 1.5 (vertex)
-1.5/2(-0.06) = -1.5/-0.12 = 12.5 is the maximum height (assuming it is in feet), 12.5 feet
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