1. Evaluate the integral from 3 to 5

Int[x/(30-x²)²]dx

2. Evaluate the integral from 0 to 4

Int[x(sqrt(x²+9)dx]

1. Int[x/(30-x²)²] = 1/[2(30-x²)]=(1/2)[1/(30-5²) -1/(30-3²)]=(1/2)(1/5 - 1/21) = about .076

2.Int[x(x² +9)^(1/2)dx] = (1/3)(x² + 9)^(3/2) = (1/3)[(4²+9)^(3/2) - (0²+9)^(3/2) ] = (1/3)[25^(3/5) - 9^(3/2)] = 98/3

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