1. Int[(x+2)/(x²+4x+3)]dx

2. Int[(lnx)²/x]dx

1. d/dx(ln(x²+4x+3)) = (2x+4)/(x²+4x+3) = 2(x+2)/(x²+4x+3) so Int[(x+2)/(x²+4x+3)] = (1/2)ln(x²+4x+3) +C

2. d/dx( {ln x}³) = 3 (ln x)²/x so Int[{(lnx)²/x}dx] = (1/3) {ln x}³ +C

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