Fe2O3(s) +3CO(g) --> 2FE(s) + 3CO2(g) What is the maximum amount of iron, in grams, which can be obtained from 454.8 grams of iron(III) oxide? Enter your answer in scientific notation.
According to the reaction, 1 mole of Fe2O3 reacts to give 2 moles of Fe. Molar mass of Fe is 56 and molar mass of Fe2O3 is 160 .
Therefore 454. 8 g of Fe2O3 will produce 112/160 x 454.8 = 318.36 g Fe
Answer: 318.36 g Fe
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