Calculate the volume of 2.59×10-3-M NaClO4 solution needed to provide 8.47×10-2 g of NaClO4.
Calculate the molality of magnesium acetate in the solution prepared by adding 43 grams of the salt to 128 grams of water.
M = mol/L
8.47×10^-2gNaClO4 (1mol / 122.44g) = 10.37mol
L = mol/M --> 10.37mol/2.59x10^-3M = 4004 L
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