Calculate the volume of 2.59×10^{-3}-M NaClO_{4} solution needed to provide 8.47×10^{-2} g of NaClO_{4}.

Calculate the molality of magnesium acetate in the solution prepared by adding 43 grams of the salt to 128 grams of water.

M = mol/L

8.47×10^-2gNaClO4 (1mol / 122.44g) = 10.37mol

L = mol/M --> 10.37mol/2.59x10^-3M = 4004 L

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