Let us say the first section pipe is AC and CE is the second section of the pipe.
The distance required is the vertical distance of point C from the ground.
= AC cos 17 + CE cos 37.
= 6.4 cos 17 + 5.2 cos 37
= 6.12 + 4.15
= 10.27 m
Answer: the end of the pipe is 10.27 m below the surface of the ground.
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