A 118-mg sample of Na_{2}CO_{3} is dissolved in H_{2}O to give 2.30L of solution.

A 118-mg sample of Na2CO3 is dissolved in H2O to give 2.30L of solution.

To calculate parts per million ( ppm)

ppm = mass of solute(mg)/ volume of solution (L)

= 118 mg/ 2.30L

= 51.30 mg/L or 51.30 ppm

What is the final molarity when 40.00 mL of a 0.803-M HClO4 solution is diluted to 660.00 mL?

To calculate the final molarity:

Used this formula: M1 V1 = M2 V2

M1 = 0.803 M

V1 = 40 mL

V2 = 660 mL

Solve for M2

M2 = M1*V1/ V2

= 0.803M * 40 mL/ 660 mL

= 0.049 M

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