A 118-mg sample of Na2CO3 is dissolved in H2O to give 2.30L of solution.
To calculate parts per million ( ppm)
ppm = mass of solute(mg)/ volume of solution (L)
= 118 mg/ 2.30L
= 51.30 mg/L or 51.30 ppm
What is the final molarity when 40.00 mL of a 0.803-M HClO4 solution is diluted to 660.00 mL?
To calculate the final molarity:
Used this formula: M1 V1 = M2 V2
M1 = 0.803 M
V1 = 40 mL
V2 = 660 mL
Solve for M2
M2 = M1*V1/ V2
= 0.803M * 40 mL/ 660 mL
= 0.049 M
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