identify the vertex and axis of symmetry of the graph of the function y=3x^2-6x+2

y = ax2 + bx + c.

Here, a = –3, b = –6, and c = 4.

Substitute a = –3 and b = –6 in the equation of axis of symmetry, x = – b/2a.

x = –1

The equation of axis of symmetry is x = –1.

Since the equation for the axis of symmetry is x = –1 and the vertex lies on the axis, the x–coordinate for the vertex is –1.

To find the y–coordinate of the vertex, substitute the value of x.

Substitute x = –1 in the given equation.

y = –3 + 6 + 4

y = 7

The coordinates of vertex are (–1, 7).

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