identify the vertex and axis of symmetry of the graph of the function y=3x^2-6x+2
y = ax2 + bx + c.
Here, a = –3, b = –6, and c = 4.
Substitute a = –3 and b = –6 in the equation of axis of symmetry, x = – b/2a.
x = –1
The equation of axis of symmetry is x = –1.
Since the equation for the axis of symmetry is x = –1 and the vertex lies on the axis, the x–coordinate for the vertex is –1.
To find the y–coordinate of the vertex, substitute the value of x.
Substitute x = –1 in the given equation.
y = –3 + 6 + 4
y = 7
The coordinates of vertex are (–1, 7).
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