identify weather the function y=3(x-2)^2+11 has a minimum or maximum value. Then state the value.
At minimum or maximum, slope = 0.
=> dy/dx = 6 ( x - 2 ) = 0
=> x = 2
=> minima or maxima at x = 2
To find which one, double differentiate to get :
d/dx ( dy/dx ) = 6 which is > 0.
Therefore, at x = 2 we have a minimum with value = 11
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?