Description
identify weather the function y=3(x-2)^2+11 has a minimum or maximum value. Then state the value.
Explanation & Answer
At minimum or maximum, slope = 0.
=> dy/dx = 6 ( x - 2 ) = 0
=> x = 2
=> minima or maxima at x = 2
To find which one, double differentiate to get :
d/dx ( dy/dx ) = 6 which is > 0.
Therefore, at x = 2 we have a minimum with value = 11
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