what is the vertex form of the equation? y=x^2-2x+8

y = x^2 - 2x + 8

x^2 - 2x + 8 = 0x^2 - 2x = -8

x^2 -2x + (-1)^2 = -8 + (-1)^2

(x - 1)^2 = -7

(x - 1)^2 + 7 = 0

The vertex form of the equation is y = (x - 1)^2 + 7.

Answer: The vertex form of the equation y = x^2 - 2x + 8 is y = (x - 1)^2 + 7.

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