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Chemistry
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The equation for the reduction of iron(III) oxide to iron metal is given by: Fe2O3(s) +3CO(g) --> 2FE(s) + 3CO2(g) What is the maximum amount of iron, in grams, which can be obtained from 623.0 grams of iron(III) oxide? Enter your answer in scientific notation. 

4.36×102

According to the equation in problem nine, what mass of carbon monoxide, in grams, is required to produce 339.5 grams of iron? Enter your answer in scientific notation.

Dec 11th, 2014

Fe2O3 + 3CO --> 2Fe + 3CO2

Molecular Weight:
1 mol Fe2CO3-- 55.85*2+12.01+16.00*3=171.71 g
1 mol Fe-- 55.85 g

Molar ratio of Fe to Fe2O3-- 2:1 (using coefficients from balanced chemical equation)

623.0 g Fe2O3 x (1 mol Fe2O3/171.71 g Fe2O3)x (2 mol Fe/1 mol Fe2O3) x (55.85 g Fe/1 mol Fe)
= 405.27 = 4.05 x 10^2 g Fe

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Molecular Weight:
1 mol CO-- 12.01+16.00=28.01 g

Molar ratio of CO to Fe-- 3:2

339.5 g Fe x (1 mol Fe/55.85 g Fe) x (3 mol CO/2 mol Fe) x (28.01 g CO/1 mol CO)
= 255.40 = 2.55 x 10^2 g CO


Dec 12th, 2014

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