Time remaining:
##### can someone help please

label Chemistry
account_circle Unassigned
schedule 0 Hours
account_balance_wallet \$5

The equation for the reduction of iron(III) oxide to iron metal is given by: Fe2O3(s) +3CO(g) --> 2FE(s) + 3CO2(g) What is the maximum amount of iron, in grams, which can be obtained from 623.0 grams of iron(III) oxide? Enter your answer in scientific notation.

4.36×102

According to the equation in problem nine, what mass of carbon monoxide, in grams, is required to produce 339.5 grams of iron? Enter your answer in scientific notation.

Dec 11th, 2014

Fe2O3 + 3CO --> 2Fe + 3CO2

Molecular Weight:
1 mol Fe2CO3-- 55.85*2+12.01+16.00*3=171.71 g
1 mol Fe-- 55.85 g

Molar ratio of Fe to Fe2O3-- 2:1 (using coefficients from balanced chemical equation)

623.0 g Fe2O3 x (1 mol Fe2O3/171.71 g Fe2O3)x (2 mol Fe/1 mol Fe2O3) x (55.85 g Fe/1 mol Fe)
= 405.27 = 4.05 x 10^2 g Fe

---------

Molecular Weight:
1 mol CO-- 12.01+16.00=28.01 g

Molar ratio of CO to Fe-- 3:2

339.5 g Fe x (1 mol Fe/55.85 g Fe) x (3 mol CO/2 mol Fe) x (28.01 g CO/1 mol CO)
= 255.40 = 2.55 x 10^2 g CO

Dec 12th, 2014

...
Dec 11th, 2014
...
Dec 11th, 2014
Sep 23rd, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer