Derivative of Inverse

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y = 7sin^-1(x^2)

I got (2x/(sqrt(49-x^4)) but I'm not sure if it is correct. Thank you.

Dec 13th, 2014

its not correct...

the formula for sine inverse is d/dx(sin^-1) = 1/(sqrt(1-x^2))

in our equation put u=x^2

d/dx(sin^-1(u)) = 7*1/(sqrt(1-u^2)) * du/dx

= 7/(sqrt(1-x^4)*2x
=14x/(sqrt(1-x^4)  (Answer)


Please best my answer and add me as your tutor for any further help. Thanks :)

Dec 13th, 2014

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Dec 13th, 2014
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Dec 13th, 2014
Oct 16th, 2017
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