In a triangle ▲ ABC, D is a point on AB . A line is drawn parallel to AB joining D and E on AC. Prove AD/DB=AE/EC
DE is parallel to AB
The triangle ADE and ABC are similar.
AD/AB = AE/AC
AD/(AB-AD) =AE/(AC-AE) (property of ratio and proportion)
AD /DB = AE /EC
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