In a triangle ▲ ABC, D is a point on AB . A line is drawn parallel to AB joining D and E on AC. Prove AD/DB=AE/EC

DE is parallel to AB

The triangle ADE and ABC are similar.

AD/AB = AE/AC

AD/(AB-AD) =AE/(AC-AE) (property of ratio and proportion)

AD /DB = AE /EC

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