an = n1/n
an+1 = (n+1)1/n+1
an+1 /an =(n+1)1/n+1/ n1/n
log an+1 /an = (1/(n+1)) ln (n+1)/(1/n)
ln(n)= n/(n+1) ln (1+1/n) -> 0 as
an+1 /an -> 1
an/an+1 -> 1
n(n+i)(n+2)/(n+1)(n+1+i)(n+3) -> 1 as n- > ∞
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