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I know the answer but how did i get it

Algebra
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4ln3x-1/3

Dec 15th, 2014

I am assuming that the value of x is required.

So the equation is 4 ln 3x -1/3 = 0

4ln(3x) = 1/3

ln (3x)^4 = 1/3

Raising to the power of e, we get

e^ ln(3x)^4 = e^1/3

(3x)^4 = e^1/3

81 x^4 = 1.396

x^4 = 1.396/81

x^4 = 0.0172

x = (0.0172) ^1/4

x = 0.362

Answer: x= 0.362

Dec 15th, 2014

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