can someone help please

Chemistry
Tutor: None Selected Time limit: 1 Day

In the reaction: KClO3 ==> KCl + O2 

159.5 g of KClO3 is reacted in a way that has a percent yield of 83 %. What mass of oxygen gas is actually produced?

Dec 15th, 2014

In the reaction: KClO3 ==> KCl + O2

159.5 g of KClO3 is reacted in a way that has a percent yield of 83 %. What mass of oxygen gas is actually produced?


Find MW of KClO3 = 106.54 g/mol

Find MW of O2 = 32 g/mol


159.5 g KCIO3 X 1 mol KClO3/ 106.54 g KClO3 X 1 mol O2/ 1 mol KClO3 = 1.50 mol O2

1.50 mol O2 X 32 g O2/ 1 mol O2 = 47.91 g O2

Since the actual percent yield is 83%.

Multiply O2 yield by 83%.

47.91 g O2 X 0.83 = 39.76 g O2.

Actual yield is 39.76 g O2.  

Dec 15th, 2014

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Dec 15th, 2014
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Dec 15th, 2014
Dec 6th, 2016
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