Calculus help: Finding derivative of (xy + x^3y) and relative extreema

Dec 16th, 2014
Price: $10 USD

Question description

I need help finding dy/dx of xy + x^3y first. To do this, do you use the product rule and the chain rule so for xy it would be (x*y' + y*1)*y' and then for x^3y it would be (x^3*y' + y*3x^2) y'? Then I also need to write the equation for the tangent line at each of the points where the x coordinate is 1, and what of these tangent lines are vertical. The original curve given is xy^2 - x^3y = 6. In addition to this, are the points where x = 1 relitive extreema? if not, how do you find relative extrema? 

I am sorry about the abundance of information there. I was home sick and really just want to get all this done, but am afraid I do not yet understand it very well. Thank you for all your help! I am not sure how to make this more clear, and I really do not know how this site works, or what the best way is for me to get help on this site. Thank you again for all your help!

Tutor Answer

(Top Tutor) Daniel C.
School: Duke University

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Dec 16th, 2014
"Thanks, good work"
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