Given with a = 24, , and ,Triangle ABC with a =24, m<A=108 deg. and m<B=33 degrees find b. Round the sine value to the nearest thousandth and the answer to the nearest hundredth.

a/ sin A = b / sin B

b = (sin B / sin A )* a

= sin 33 / sin 108 * 24

=0.5446/0.9510 * 24= 13.74

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