Given Triangle ABC with a = 12, b = 6, and m<A=50 degrees , find m<B . Round the sine value to the nearest thousandth and answer to the nearest whole degree.

10°

23°

107°

114°

23 degrees

a/sin A = b /sin B

sin B = b* sin A/a =6/12 * sin 50 =0.766/2= 0.383

B = sin ^{-1 } (0.383) =22.52^{0 } =23^{0 }

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