Given Triangle ABC with b = 21, c = 32, and m<A=40 degrees , find a. Round the cosine value to the nearest thousandth and answer to the nearest hundredth.
=b2+c2-2bc Cos A
=441+1024-2*21*32 * 0.766 = 435.44
a = sqrt(435.44) 20.87
Answer: a =20.87
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