Trig Question 7

Mathematics
Tutor: None Selected Time limit: 1 Day

Given Triangle ABC  with b = 21, c = 32, and m<A=40 degrees  , find a. Round the cosine value to the nearest thousandth and answer to the nearest hundredth.

Dec 16th, 2014

a2 =b2+c2-2bc Cos A

 a2 = 212+322-2*21*32* cos 40

    =441+1024-2*21*32 * 0.766 = 435.44

a = sqrt(435.44) 20.87

Answer: a =20.87

Dec 16th, 2014

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