Given Triangle ABC with b = 21, c = 32, and m<A=40 degrees , find a. Round the cosine value to the nearest thousandth and answer to the nearest hundredth.

20.33

20.87

22.43

33.78

a^{2} =b^{2}+c^{2}-2bc Cos A

=441+1024-2*21*32 * 0.766 = 435.44

a = sqrt(435.44) 20.87

Answer: a =20.87

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