Given Triangle ABC with a = 6, b = 18, and m<C=88 deg , find c. Round the cosine value to the nearest thousandth and answer to the nearest hundredth.

8.88

15.75

18.77

28.32

c^{2} =a^{2}+b^{2}-2ab Cos C

a^{2} = 6^{2}+18^{2}-2*6*18* cos 88

=352.4617

a = sqrt(352.4617) =18.77

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