Lim f(x) = 0
as x -> ∞
When x >
n0 then f(x) < small
number epsilon . If we take this as .0000001, it is true that f(x) <
let us take f(x)=1/x
If x >
1/0.00000001 =108 > 100 million, then f(x) < 0.00000001
First statement is true
will be approached but not attained.
is no finite x for which f(x) =0
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