. After 130 minutes at 240 degrees Celsius 96% of the COOH and NH2 groups had reacted. Calculate the value of CoK where Co is the concentration of monomer t=0 and k is the rate constant.
This is a second
order reaction since Monomer 1 + Monomer 2 = Polymer
rate low for a second order reaction is: Rate = - ∆ Co/2∆t=k [Polymer]2
1/[Monomer] + kt
[Polymer]t - 1/t = [Monomer]k (This is the value that you need to find)
96% was polymerized, then you can let value [Monomer]=1M, and value [Polymer]=
(1/(0.96x130min) - 1/130 min = [Monomer]k
- 0.0077 = [Monomer]k
– 0.0077 = [Monomer]k = 0.00031 or 3.1 x 10 -4 sec-
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