use the law of cosines to solve the triangle

label Calculus
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use the law of cosines to solve the triangle

a=10 b=12 c=16

Dec 17th, 2014

cos A = (b2+c2-a2)/(2bc)

cos B = (c2+a2-b2)/(2ca)

cos C = (a2+b2-c2)/(2ab)


Cos A = (144+256-100)/(2*12*16) = 300/384

A = 38.62 Degrees

Cos B = (256+100-144)/(2*16*10)= 212/320

B = 48.51 degrees

Cos C = (100+144-256)/(2*10*12) =-12 /240 

C = 92.87 degrees

Dec 17th, 2014

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Dec 17th, 2014
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