What is the final molarity when 40.00 mL of a 0.803-M HClO4 solution is diluted to 660.00 mL?
Calculate the molarity of diluted NaSCN if 20.00 mL of 0.351 M NaSCN is transfered to a 100.00 mL volumetric flask, diluted to the mark and mixed well?
This problem is solved by the dilution formula: M1V1 = M2V2
Here, you are looking for the initial
concentration which is denoted M1, thus:
M1 x 100.00 mL = 20.00 mL x 0.351 M
M1 = 0.070 M is the final answer.
Hope the answer was within 5 minutes :)
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