Find the exact value for cos2x given sinx= square route of 2/4

0

3/4

1

2

cos(2x) = cos(x)^2 - sin(x)^2 = 1 - 2sin(x)^2 sin(x) = sqrt(2/4) sin(x)^2 = 2/4 = 1/2 1 - 2 * (1/2) = 1 - 1 = 0 Unless you meant: sin(x) = sqrt(2) / 4 sin(x)^2 = 2/16 = 1/8 1 - 2 * (1/8) = 1 - 1/4 = 3/4

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