trig Identities 5

Mathematics
Tutor: None Selected Time limit: 1 Day

Find the exact value for cos2x  given   sinx= square route of 2/4

Dec 17th, 2014

cos(2x) = 
cos(x)^2 - sin(x)^2 = 
1 - 2sin(x)^2 

sin(x) = sqrt(2/4) 
sin(x)^2 = 2/4 = 1/2 

1 - 2 * (1/2) = 
1 - 1 = 


Unless you meant: sin(x) = sqrt(2) / 4 
sin(x)^2 = 2/16 = 1/8 

1 - 2 * (1/8) = 
1 - 1/4 = 
3/4

Dec 17th, 2014

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