##### trig Identities 15

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Solve the following equation for :  0<x<pie: 2cos^x+3sinx-3=0 Select all that apply.

 0 pie/6 pie/2 5pie/6
Dec 17th, 2014

cos^2(x) = 1 - sin^2(x) (Pythagorean identity)
2(1 - sin^2(x)) + 3sin(x) - 3 = 0 (substitution)
2 - 2sin^2(x) + 3sin(x) - 3 = 0 (distributive prop)
-2sin^2(x) + 3sin(x) - 1 = 0 (combining like terms)
2sin^2(x) - 3sin(x) + 1 = 0 (X both sides by -1)
(2sin(x) - 1)(sin(x) - 1) = 0 (factored LHS)
2sin(x) - 1 = 0 or sin(x) - 1 = 0 (zero product rule)
sin(x) = 1/2 or sin(x) = 1 (solve for sin(x))
x = 30 deg, 150 deg or 90 deg (sin(30 deg) = sin(150 deg) = 1/2, sin(90 deg) = 1
In radians, your answers are pi/6, 5pi/6, pi/2.

Dec 17th, 2014

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Dec 17th, 2014
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Dec 17th, 2014
Sep 21st, 2017
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