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Mathematics
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What is i^29

Dec 18th, 2014

i = cos pi/2 +i sin pi/2

i ^29 = cos 29pi/2+isin 29pi/2 = isin pi/2 = i

i^29=i

Alternatively i ^29 = i^28 * i = 1^7 * i =1

since i^4 =1

Answer: i

Dec 18th, 2014

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