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Fifty tickets, numbered consecutively from 1 to 50 are placed in a jar. Two tick

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Fifty tickets, numbered consecutively from 1 to 50 are placed in a jar. Two tickets are drawn at random (without replacement).

-What is the probability that the difference of the two number is 10 or less?
Dec 19th, 2014

If the number is x for 1<=x,+40, there are 10 choices. 40*10

If it is 41, then 9 choices. If 42 there are 8 choices..if it is 49 ,one choice. Thus 9+8+..1= 9*10/2 =45

Thus there are 400+45 = 445 choices possible

The total number of ways = 50*49/2 = 25*49 = 1225

The probability is 445/1225 = 89/225

Dec 19th, 2014

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