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Mathematics
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f(z) = sin ( 1/(z-pi)) / 2z
1- Find the singularities of f , and all possible annulus centered at each singularity 
2- Find the laurent series of f in each annulus
3- classify each singularity 

4- compute the residue of at each singular point

Dec 20th, 2014

f(z)=(1/2)*(1/z)*sum(from 0 to inf){(-1)^n*(1/(z-pi))^(2n+1)/((2n+1)!)}

and you know the solution of 1/(z-pi), so plug that in

Dec 22nd, 2014

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Dec 20th, 2014
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Dec 20th, 2014
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