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When a metallic ball bearing is placed inside a cylindrical container, of radius 2 cm, the height of the water, inside the container, increases by 0.6 cm. The radius, to the nearest tenth of a centimeter, of the ball bearing is.. 


Dec 22nd, 2014

so ok here is your answer > When the ball was put in water, the volume of water increased by.

pi*22*0.6 = 2.4 pi cubic cm 

The above volume is equal to the volume of the ball with radius r to find. Hence

(4/3)*pi*r3 = 2.4 pi 

Solve the above for r

r = 1.2 cm

Dec 22nd, 2014

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Dec 22nd, 2014
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Dec 22nd, 2014
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