When a metallic ball bearing is placed inside a cylindrical container, of radius 2 cm, the height of the water, inside the container, increases by 0.6 cm. The radius, to the nearest tenth of a centimeter, of the ball bearing is..

so ok here is your answer > When the ball was put in water, the volume of water increased by.pi*2^{2}*0.6 = 2.4 pi cubic cm The above volume is equal to the volume of the ball with radius r to find. Hence(4/3)*pi*r^{3} = 2.4 pi Solve the above for rr = 1.2 cm

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