Time remaining:
Full Details please

label Mathematics
account_circle Unassigned
schedule 0 Hours
account_balance_wallet $5

Dec 25th, 2014



z7 sum (-1)n z2n  from 0 to infinity = z7/(1+z2)

i = cos pi/2+ i sin ppi/2

i(2n+3)i =exp( i pi/2)(2n+3)i = exp(-(2n+3)pi/2) = e-(2n+3)pi/2

| (-1)ni(2n+3)i | =| e-(2n+3)pi/2 |

Zn+1/zn  = e-(2n+5)pi/2+(2n+3)pi/2= e-pi = 1/epi < 1

Hence the series is convergent

Sum (-1)n e-(2n+3)pi/2 from 2 to infinity

= e-3pi/2 sum (-1)n (e-pi)n from 2 to infinity

= e-7pi/2 sum (-1)n(epi)n from 0 to infinity

e-7pi/2 /(1+epi)

Dec 24th, 2014

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
Dec 25th, 2014
Dec 25th, 2014
Jun 28th, 2017
Mark as Final Answer
Unmark as Final Answer
Final Answer

Secure Information

Content will be erased after question is completed.

Final Answer