Write the equation of a line in point-slope form that has a slope of and passes through the point(-6, 0).
The point-slope form of a line is of the form
y - y1 = m(x-x1)
where m is the slope and (x1,y1) is the point.
y - 0 = 1/3(x- -6)
You can simplify a little bit:
y = 1/3(x+6)
but that's nearly no longer in point-slope form.
You can simplify a bit more too...
y = x/3 + 2
but now that's defintely not in pointy/slope form!
So equation will be y=1/3x+2
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