Write the equation of a line in point-slope form that has a slope of and passes through the point(-6, 0).

The point-slope form of a line is of the form

y - y1 = m(x-x1)

where m is the slope and (x1,y1) is the point.

So, substitute!

y - 0 = 1/3(x- -6)

You can simplify a little bit:

y = 1/3(x+6)

but that's nearly no longer in point-slope form.

You can simplify a bit more too...

y = x/3 + 2

but now that's defintely not in pointy/slope form!

So equation will be y=1/3x+2

Choose me best answer!

Merry

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