Find the number of integer solutions of the equation n1+n2+n3+n4=153

with n1>=10, n2>=20, n3>=30, n4>=40

Since ensuring minimum 10,20,30,40 yielding sum of 100,

the new n1,n2,n3,n4 will satisfy

n1+n2+n3+n4 = 53

This can be done in _{(53+4-1)}C_{(4-1)} = _{56}C_{3} = 56*55*54/6 = 56*55*9= 27720 Using Bose Einstein Statistics

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