which satisfies all four congruences:

x==2(mod15), x==3(mod14), x==4(mod13), x==5(mod11)

If x = 17 , then all are possible.

x==2(mod15), 17==2(mod15),

x==3(mod14), 17==3(mod14),

x==4(mod13), 17==4(mod13),

x==5(mod11) 17==5(mod11)

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