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 What is the mass of 1.507E+23 atoms of gold?

Dec 26th, 2014

Mass of one atom of gold= 196.97/(6.022*10^23) = 3.2706*10^(-22)

Mass of 1.507*10^23 = 1.507*10^23*3.2706*10^(-22)= 49.3 grams

Answer: 49.3 grams

Dec 26th, 2014

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