A chemist wishes to make 2 liters of a 6% acid solution by mixing a 9% acid solution and a 4% acid solution. How many liters of each solution should the chemist use?

Let x be liters of 9% acid solution required. So 2-x is liters of 4% acid solution required.

Therefore the equation is: x times 9 + (2-x) times 4 = 2 times 6

So 9x +8-4x = 12

5x + 8 = 12

Take away 8 from both sides.

5x+8-8 =12-8

5x= 4

x=4/5

Therefore 4/5 liter or 0.8 liter of 9% solution and 1 1/5 liter or 1.2 liter of 4% solution required

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