Following presents left to unwrap:one from A, three from B and three from C. How many ways to arrange these presents in the form of a circle if no two presents from person B can be placed one next to another?
total 7 presents can be used to form circle in (7-1)! ways = 6! ways
of which 3 gifts of can be together so we need to find the way in
which all the gifts can be placed next to each other = (5-1)! = 4! waysand 3 gifts can arrange themselves in 3! ways.and 2 gifts can be considered as 1 and can be arranged in = (6-1)! = 5! waysand 2 gifts can arrange themselves in = 2! waysso the no. of ways = 6! - [(4!*3!) + (*5!*2!)]
= 720- [(24*6)+(120*2)]=720-[144+240] = 336 ways (answer)Please best my answer. Thanks :)
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