please can you help within five minutes

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The half life of 14C is 5730 years. What fraction of the 14C nuclei in a sample are left after 7060 years?

Jan 1st, 2015

the formula is A = Ao (1/2)^(t/h)

where, A is the final amount
Ao is the initial amount
t = time
h= half life

so, A = Ao (1/2)^(7060/5730)
or, (A/Ao) = (1/2)^ 1.232 = 0.4257

so, the fraction of 14C left  = 0.4257 of initial amount.


Please best my answer if helpful. Happy New Year :)

Jan 1st, 2015

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