The half life of 14C is 5730 years. What fraction of the 14C nuclei in a sample are left after 7060 years?
the formula is A = Ao (1/2)^(t/h)
where, A is the final amountAo is the initial amountt = timeh= half lifeso, A = Ao (1/2)^(7060/5730)or, (A/Ao) = (1/2)^ 1.232 = 0.4257so, the fraction of 14C left = 0.4257 of initial amount.Please best my answer if helpful. Happy New Year :)
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