with a rate constant of 3.56×10^{-1} M^{-1}hr^{-1}. The initial concentration of the reactant A is 0.24 M. Calculate the concentration of A after 25.0 hr.

The formula for calculation this type of problem is

N = No e^{-ᵞ t}

N = 0.24 e ^{-0.356x25} = 0.24 e ^{– 8.9} = 0.24/e^{8.9 }= 0.24/73331.97 = 0.000003273 = 3.27 x 10^{ 6}M

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