please help within five minutes

Chemistry
Tutor: None Selected Time limit: 1 Day

Substance A undergoes a reaction which follows a second order rate law: 

[A]t = 1

1/[A]0 + kt
with a rate constant of 3.56×10-1 M-1hr-1. The initial concentration of the reactant A is 0.24 M. Calculate the concentration of A after 25.0 hr. 
Jan 2nd, 2015

Plug in .24 for A 

.24A= 1/1[.24]+it 

.24(25hr) =1/.24kt 

.24(25hr)=4.1kt

Hope I helped :)


Jan 2nd, 2015

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