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. If 5.01 moles of aluminum are reacted, how many moles of hydrogen will be produced?

If 59.1 g of hydrogen sulfate is reacted, what mass of aluminum sulfate is produced?

Jan 2nd, 2015

Assuming you are talking about the reaction

2Al + 3H2SO4 ==== Al2(SO4)3 + 3H2

The molar ration between H2 and Al is 3:2.

So when 5.01 moles of aluminum are reacted, 5.01x3/2=7.52 moles of H2 will be produced.

The molar mass of H2SO4= 2+32+16x4=98 g/mol.

So the moles of H2SO4=59.1/98=0.603 mole.

The molar ratio between Al2(SO4)3 and H2SO4 is 1:3.

So when 0.603 moles of H2SO4 is reacted, 0.603x1/3=0.201 moles of Al2(SO4)3 is produced.

The molar mass of Al2(SO4)3=27x2+(32+16x4)x3=342 g/mol

So the mass of Al2(SO4)3=342x0.201=68.7 g

Jan 2nd, 2015

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