. If 5.01 moles of aluminum are reacted, how many moles of hydrogen will be produced?
If 59.1 g of hydrogen sulfate is reacted, what mass of aluminum sulfate is produced?
Assuming you are talking about the reaction
2Al + 3H2SO4 ==== Al2(SO4)3 + 3H2
The molar ration between H2 and Al is 3:2.
So when 5.01 moles of aluminum are reacted, 5.01x3/2=7.52 moles of H2 will be produced.
The molar mass of H2SO4= 2+32+16x4=98 g/mol.
So the moles of H2SO4=59.1/98=0.603 mole.
The molar ratio between Al2(SO4)3 and H2SO4 is 1:3.
So when 0.603 moles of H2SO4 is reacted, 0.603x1/3=0.201 moles of Al2(SO4)3 is produced.
The molar mass of Al2(SO4)3=27x2+(32+16x4)x3=342 g/mol
So the mass of Al2(SO4)3=342x0.201=68.7 g
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