A 3kg mass is attached to the end of light rod and made to move clockwise in a vertical circle of radius of 2m and speed of 6m/s. the tension in the rod at the lowest point most nearly..
T = m(g+v^2/r) = 3kg x (9.8m/s/s + (6m/s)^2/2m) = 83.4N 2. the horizontal force = 4 cos 45 = 2.83N F = m a so that a = F/m = 2,8N/2kg = 1.4m/s/s
best of luck ......................
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