Description
Please see the attached WORD and excel documents for your to complete in its entirety. If you have any questions please feel free to contact me.
Unformatted Attachment Preview
Purchase answer to see full attachment
Explanation & Answer
Here is my answer :)
1. (2 points) A claim is made that when parents use the XSORT method of gender selection during invitro fertilization, the proportion of baby girls is greater than 0.5. The latest results show that among
945 babies born to couples using the XSORT method of gender selection, 879 were girls.
a. (1 point) Express the original claim in symbolic form.
p > 0.50
b. (1 point) Identify the null and alternative hypothesis.
H0 : p = 0.50
Ha ∶ p > 0.50
2. (10 points) A 0.05 significance level is used for a hypothesis test of the claim that when parents use the
XSORT method of gender selection, the proportion of baby girls is different from 0.5. Assume that the
data consists of 55 girls born in 100 births, so the sample statistic of 0.55 results in a z-score that is 1.00
standard deviation above 0.
a. (1 point) Identify the null and alternative hypothesis.
To test the hypothesis is that the proportion of baby girls is different from 0.50
The null and alternative hypothesis is,
H0 : p = 0.50
Ha ∶ p ≠ 0.50
b. (1 point) What is the value of α?
The value of level of significance is α = 0.05
c. (1 point) What is the sampling distribution of the sample statistic?
The mean of the sampling distribution of the sample statistic is,
μp̂ = p
μp̂ = 0.55
The standard deviation of the sampling distribution of the sample statistic is,
𝜎𝑝̂ = √
𝑝(1 − 𝑝)
𝑛
(0.50)(1 − 0.50)
100
𝜎𝑝̂ = 0.05
𝜎𝑝̂ = √
Page 1 of 8
d. (1 point) Is this a two-tailed, left-tailed, or right-tailed test? Why?
The test is two-tailed due to the alternative hypothesis is that the proportion of baby girls is different
from 0.50
e. (1 point) What i...