Using the stop watch you will calculate the time it takes the object to leave the ground and land on the

ground. Initial velocity - v_0

time at which the sticky bomb was at the highest point.

maximum height of the object.

all steps shown

h(t) = -16t^2 + Vot + c

= -16 (t^2 - 1/16 Vot) + c {take out -16 and be careful to change sign inside bracket]

= -16 (t^2 -1/16 Vot + 1/1024 Vo^2) + 16 * 1/1024Vo^2 + c

[complete the square by adding the square of half the coefficient of t, (1/32 Vo)² =1/1024Vo^2

and compensate for the subtraction]

= -16 (t - 1/32Vo)^2 -1/64Vo^2 + c

= -16 (t - 1/32Vo)^2 + c- 1/64Vo^2

It will reach maximum height when t = 1/32Vo reaching height of c- 1/64 Vo^2

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