What is the percent yield of water if 0.90 g of water is obtained when 29.0 g of

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What is the percent yield of water if 0.90 g of water is obtained when 29.0 g of butane is burned in excess oxygen? The balanced chemical equation is...

(a)0.02%
(b)2%
(c)10%
(d)36%
Jan 9th, 2015

butane is C4H10 the mass of 1 mole butane is 4*12+10*1 = 58 g 

2C4H10 + 9O2  ---> 4CO2 +10H2O

2*58                                       10*18

29                                             10*18/4 

so the % yield is 0.9/ (45) = 2%.                                                 


Jan 9th, 2015

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