At equilibrium at 1.0 L vessel contains 17.00
mol of H2, 20.00 mol of CO2, 13.00 mol of
H2O, and 6.000 mol of CO at 427◦C.
CO2(g) + H2(g) ⇀↽ CO(g) + H2O(g)
What is the value of K at this temperature
for the reaction?
the value of K is
K = [CO][H2O]/([CO2][H2]) = 6*13/(20*17) = 0.229
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