Description
At equilibrium at 1.0 L vessel contains 17.00
mol of H2, 20.00 mol of CO2, 13.00 mol of
H2O, and 6.000 mol of CO at 427◦C.
CO2(g) + H2(g) ⇀↽ CO(g) + H2O(g)
What is the value of K at this temperature
for the reaction?
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Explanation & Answer
K = [H2O] [CO]/{ [CO2] [H2] = 13*6/(17*20) =78/340 =0.2294 = 0.23
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