Fe (s) + S (s) = Fe2S3 (s) How many grams (to 0.01 g) of Fe2S3 could be produced

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Fe (s) + S (s) = Fe2S3 (s)

How many grams (to 0.01 g) of Fe2S3 could be produced by reacting 3.67 g of iron with an unlimited amount of sulfur
Jan 12th, 2015

2 Fe + 3 SFe2S3.

mass number of Fe=55.8

moles of Fe= 3.67g/55.8=0.06577moles

mole ratio= Fe: Fe2S3=2:1

moles of Fe2S3=1/2*0.06577moles

=0.0328853 moles

mass number of Fe2S3=207.88

grams of Fe2S3= O.O328853*207.88

=6.836197 GRAMS

6.84 GRAMS    (2 DECIMAL PLACES)

please best my answer. welcome

Jan 12th, 2015

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Jan 12th, 2015
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Jan 12th, 2015
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