If a chemist experimentally determined the percent carbon in C3H8 to be 79.43 %,

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If a chemist experimentally determined the percent carbon in C3H8 to be 79.43 %, what was his % error (to 0.01 %)? (Hint - you already know how to determine the theoretical % C in C3H8.)

Oct 20th, 2017

Molar mass of C3H8 is 44.0956 g/mol

%of carbon=12/44.0956*100%27.21%

percentage error=79.43%-27.21%

=52.22%

therefore percentage error=52.22/27.21*100%

=191.91%

please best my answer

Jan 13th, 2015

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